Base | Representation |
---|---|
bin | 110010000100111010101… |
… | …010100100110101011111 |
3 | 110011222110211201101112211 |
4 | 302010322222210311133 |
5 | 422340141234343201 |
6 | 11152520111341251 |
7 | 503423313146101 |
oct | 62047252446537 |
9 | 13158424641484 |
10 | 3441253043551 |
11 | 11074776a22a4 |
12 | 476b30821827 |
13 | 1bc67c9c778b |
14 | bc7b3c43571 |
15 | 5e7acb3b651 |
hex | 3213aaa4d5f |
3441253043551 has 4 divisors (see below), whose sum is σ = 3443922752400. Its totient is φ = 3438583334704.
The previous prime is 3441253043549. The next prime is 3441253043567. The reversal of 3441253043551 is 1553403521443.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 3441253043551 - 21 = 3441253043549 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3441253043651) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1334852491 + ... + 1334855068.
It is an arithmetic number, because the mean of its divisors is an integer number (860980688100).
Almost surely, 23441253043551 is an apocalyptic number.
3441253043551 is a deficient number, since it is larger than the sum of its proper divisors (2669708849).
3441253043551 is a wasteful number, since it uses less digits than its factorization.
3441253043551 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2669708848.
The product of its (nonzero) digits is 432000, while the sum is 40.
Adding to 3441253043551 its reverse (1553403521443), we get a palindrome (4994656564994).
The spelling of 3441253043551 in words is "three trillion, four hundred forty-one billion, two hundred fifty-three million, forty-three thousand, five hundred fifty-one".
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