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3442012011403 = 7491716001629
BaseRepresentation
bin110010000101100111111…
…001110011101110001011
3110012001102201211221201021
4302011213321303232023
5422343220033331103
611153123302533311
7503451160235260
oct62054771635613
913161381757637
103442012011403
111107827058059
12477102a37237
131bc771012094
14bc84696b267
155e8045aabbd
hex32167e73b8b

3442012011403 has 4 divisors (see below), whose sum is σ = 3933728013040. Its totient is φ = 2950296009768.

The previous prime is 3442012011391. The next prime is 3442012011433. The reversal of 3442012011403 is 3041102102443.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 3442012011403 - 229 = 3441475140491 is a prime.

It is not an unprimeable number, because it can be changed into a prime (3442012011433) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 245858000808 + ... + 245858000821.

It is an arithmetic number, because the mean of its divisors is an integer number (983432003260).

Almost surely, 23442012011403 is an apocalyptic number.

3442012011403 is a deficient number, since it is larger than the sum of its proper divisors (491716001637).

3442012011403 is an equidigital number, since it uses as much as digits as its factorization.

3442012011403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 491716001636.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 3442012011403 its reverse (3041102102443), we get a palindrome (6483114113846).

The spelling of 3442012011403 in words is "three trillion, four hundred forty-two billion, twelve million, eleven thousand, four hundred three".

Divisors: 1 7 491716001629 3442012011403