Base | Representation |
---|---|
bin | 100000000011110111… |
… | …000011001111110011 |
3 | 10021212002202212001020 |
4 | 200003313003033303 |
5 | 1031000133014420 |
6 | 23451524310523 |
7 | 2326033301235 |
oct | 400367031763 |
9 | 107762685036 |
10 | 34424501235 |
11 | 13665808323 |
12 | 6808842443 |
13 | 3327c26277 |
14 | 1947d00255 |
15 | d672a2340 |
hex | 803dc33f3 |
34424501235 has 16 divisors (see below), whose sum is σ = 57473950464. Its totient is φ = 17561484512.
The previous prime is 34424501233. The next prime is 34424501239. The reversal of 34424501235 is 53210542443.
34424501235 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a cyclic number.
It is not a de Polignac number, because 34424501235 - 21 = 34424501233 is a prime.
It is a super-3 number, since 3×344245012353 (a number of 33 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 34424501196 and 34424501205.
It is not an unprimeable number, because it can be changed into a prime (34424501233) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 49890237 + ... + 49890926.
It is an arithmetic number, because the mean of its divisors is an integer number (3592121904).
Almost surely, 234424501235 is an apocalyptic number.
34424501235 is a deficient number, since it is larger than the sum of its proper divisors (23049449229).
34424501235 is a wasteful number, since it uses less digits than its factorization.
34424501235 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 99781194.
The product of its (nonzero) digits is 57600, while the sum is 33.
The spelling of 34424501235 in words is "thirty-four billion, four hundred twenty-four million, five hundred one thousand, two hundred thirty-five".
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