Base | Representation |
---|---|
bin | 110010000110101010100… |
… | …111111110111010011001 |
3 | 110012011022202012101211010 |
4 | 302012222213332322121 |
5 | 422403013120141441 |
6 | 11153430331324133 |
7 | 503521002053232 |
oct | 62065247767231 |
9 | 13164282171733 |
10 | 3443131412121 |
11 | 1108250a13415 |
12 | 4773758b0649 |
13 | 1bc8bbbc647b |
14 | bc9114ba089 |
15 | 5e86c9c5116 |
hex | 321aa9fee99 |
3443131412121 has 16 divisors (see below), whose sum is σ = 4761601069248. Its totient is φ = 2211269832000.
The previous prime is 3443131412101. The next prime is 3443131412129. The reversal of 3443131412121 is 1212141313443.
It is not a de Polignac number, because 3443131412121 - 215 = 3443131379353 is a prime.
It is a super-2 number, since 2×34431314121212 (a number of 26 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (3443131412129) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 153549195 + ... + 153571616.
It is an arithmetic number, because the mean of its divisors is an integer number (297600066828).
Almost surely, 23443131412121 is an apocalyptic number.
It is an amenable number.
3443131412121 is a deficient number, since it is larger than the sum of its proper divisors (1318469657127).
3443131412121 is a wasteful number, since it uses less digits than its factorization.
3443131412121 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 307120952.
The product of its digits is 6912, while the sum is 30.
Adding to 3443131412121 its reverse (1212141313443), we get a palindrome (4655272725564).
The spelling of 3443131412121 in words is "three trillion, four hundred forty-three billion, one hundred thirty-one million, four hundred twelve thousand, one hundred twenty-one".
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