Base | Representation |
---|---|
bin | 100111001001010010011001… |
… | …1111010000001011011000111 |
3 | 1200011011001200211102110101220 |
4 | 1032102210303322001123013 |
5 | 330112401231111014343 |
6 | 3220152150520051423 |
7 | 132345411166231413 |
oct | 11622446372013307 |
9 | 1604131624373356 |
10 | 344324104001223 |
11 | 9a79203a21a325 |
12 | 32750399903b73 |
13 | 11a18815307a08 |
14 | 6105538741d43 |
15 | 29c19d7dcb183 |
hex | 1392933e816c7 |
344324104001223 has 16 divisors (see below), whose sum is σ = 466667334581376. Its totient is φ = 225765820614240.
The previous prime is 344324104001219. The next prime is 344324104001231. The reversal of 344324104001223 is 322100401423443.
It is not a de Polignac number, because 344324104001223 - 22 = 344324104001219 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (344324104001243) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 83297761 + ... + 87333642.
It is an arithmetic number, because the mean of its divisors is an integer number (29166708411336).
Almost surely, 2344324104001223 is an apocalyptic number.
344324104001223 is a deficient number, since it is larger than the sum of its proper divisors (122343230580153).
344324104001223 is a wasteful number, since it uses less digits than its factorization.
344324104001223 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 170642494.
The product of its (nonzero) digits is 55296, while the sum is 33.
Adding to 344324104001223 its reverse (322100401423443), we get a palindrome (666424505424666).
The spelling of 344324104001223 in words is "three hundred forty-four trillion, three hundred twenty-four billion, one hundred four million, one thousand, two hundred twenty-three".
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