Base | Representation |
---|---|
bin | 100000000100010101… |
… | …100100000110110101 |
3 | 10021212122211020111022 |
4 | 200010111210012311 |
5 | 1031004210001044 |
6 | 23452411550525 |
7 | 2326161264545 |
oct | 400425440665 |
9 | 107778736438 |
10 | 34432500149 |
11 | 1366a280aa3 |
12 | 680b45b445 |
13 | 3329797058 |
14 | 1948dc3325 |
15 | d67d323ee |
hex | 8045641b5 |
34432500149 has 4 divisors (see below), whose sum is σ = 34433243136. Its totient is φ = 34431757164.
The previous prime is 34432500127. The next prime is 34432500163. The reversal of 34432500149 is 94100523443.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 34432500149 - 220 = 34431451573 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (34432500199) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 296999 + ... + 396324.
It is an arithmetic number, because the mean of its divisors is an integer number (8608310784).
Almost surely, 234432500149 is an apocalyptic number.
It is an amenable number.
34432500149 is a deficient number, since it is larger than the sum of its proper divisors (742987).
34432500149 is an equidigital number, since it uses as much as digits as its factorization.
34432500149 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 742986.
The product of its (nonzero) digits is 51840, while the sum is 35.
The spelling of 34432500149 in words is "thirty-four billion, four hundred thirty-two million, five hundred thousand, one hundred forty-nine".
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