Base | Representation |
---|---|
bin | 100000000100011000… |
… | …010110110010000001 |
3 | 10021212201012102101221 |
4 | 200010120112302001 |
5 | 1031004401411001 |
6 | 23452435355041 |
7 | 2326200433330 |
oct | 400430266201 |
9 | 107781172357 |
10 | 34433232001 |
11 | 1366a730933 |
12 | 680b752a81 |
13 | 33299921bc |
14 | 1949133d17 |
15 | d67e291a1 |
hex | 804616c81 |
34433232001 has 4 divisors (see below), whose sum is σ = 39352265152. Its totient is φ = 29514198852.
The previous prime is 34433231947. The next prime is 34433232013. The reversal of 34433232001 is 10023233443.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 34433232001 - 217 = 34433100929 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (34433232061) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (11) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2459516565 + ... + 2459516578.
It is an arithmetic number, because the mean of its divisors is an integer number (9838066288).
Almost surely, 234433232001 is an apocalyptic number.
It is an amenable number.
34433232001 is a deficient number, since it is larger than the sum of its proper divisors (4919033151).
34433232001 is an equidigital number, since it uses as much as digits as its factorization.
34433232001 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4919033150.
The product of its (nonzero) digits is 5184, while the sum is 25.
Adding to 34433232001 its reverse (10023233443), we get a palindrome (44456465444).
The spelling of 34433232001 in words is "thirty-four billion, four hundred thirty-three million, two hundred thirty-two thousand, one".
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