34440122420133 has 4 divisors (see below), whose sum is σ = 45920163226848. Its totient is φ = 22960081613420.

The previous prime is 34440122420111. The next prime is 34440122420153. The reversal of 34440122420133 is 33102422104443.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 34440122420133 - 2⁸ = 34440122419877 is a prime.

It is a super-2 number, since 2×34440122420133² (a number of 28 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 34440122420094 and 34440122420103.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (34440122420153) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5740020403353 + ... + 5740020403358.

It is an arithmetic number, because the mean of its divisors is an integer number (11480040806712).

Almost surely, 2^{34440122420133} is an apocalyptic number.

It is an amenable number.

34440122420133 is a deficient number, since it is larger than the sum of its proper divisors (11480040806715).

34440122420133 is a wasteful number, since it uses less digits than its factorization.

34440122420133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11480040806714.

The product of its (nonzero) digits is 55296, while the sum is 33.

Adding to 34440122420133 its reverse (33102422104443), we get a palindrome (67542544524576).

The spelling of 34440122420133 in words is "thirty-four trillion, four hundred forty billion, one hundred twenty-two million, four hundred twenty thousand, one hundred thirty-three".