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34441243303 = 231497445361
BaseRepresentation
bin100000000100110110…
…111010101010100111
310021220021021102211211
4200010312322222213
51031013424241203
623453323212251
72326325511025
oct400466725247
9107807242754
1034441243303
1113674202945
126812377087
13332b53880c
14194a21b715
15d689acc6d
hex804dbaaa7

34441243303 has 4 divisors (see below), whose sum is σ = 35938688688. Its totient is φ = 32943797920.

The previous prime is 34441243297. The next prime is 34441243307. The reversal of 34441243303 is 30334214443.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 30334214443 = 132333401111.

It is not a de Polignac number, because 34441243303 - 225 = 34407688871 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (34441243307) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 748722658 + ... + 748722703.

It is an arithmetic number, because the mean of its divisors is an integer number (8984672172).

Almost surely, 234441243303 is an apocalyptic number.

34441243303 is a deficient number, since it is larger than the sum of its proper divisors (1497445385).

34441243303 is a wasteful number, since it uses less digits than its factorization.

34441243303 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1497445384.

The product of its (nonzero) digits is 41472, while the sum is 31.

Adding to 34441243303 its reverse (30334214443), we get a palindrome (64775457746).

The spelling of 34441243303 in words is "thirty-four billion, four hundred forty-one million, two hundred forty-three thousand, three hundred three".

Divisors: 1 23 1497445361 34441243303