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34441352243314 = 217220676121657
BaseRepresentation
bin1111101010011000000001…
…00100001110100001110010
311111221120011001111110000021
413311030000210032201302
514003241342133241224
6201130045551314054
710153206546514432
oct765140044164162
9144846131443007
1034441352243314
11aa7954a503515
123a42b6b21b92a
13162aa61b25a33
14870d8289a2c2
153ead72c241e4
hex1f530090e872

34441352243314 has 4 divisors (see below), whose sum is σ = 51662028364974. Its totient is φ = 17220676121656.

The previous prime is 34441352243273. The next prime is 34441352243329. The reversal of 34441352243314 is 41334225314443.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 34242451407025 + 198900836289 = 5851705^2 + 445983^2 .

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8610338060827 + ... + 8610338060830.

Almost surely, 234441352243314 is an apocalyptic number.

34441352243314 is a deficient number, since it is larger than the sum of its proper divisors (17220676121660).

34441352243314 is a wasteful number, since it uses less digits than its factorization.

34441352243314 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 17220676121659.

The product of its digits is 1658880, while the sum is 43.

Adding to 34441352243314 its reverse (41334225314443), we get a palindrome (75775577557757).

The spelling of 34441352243314 in words is "thirty-four trillion, four hundred forty-one billion, three hundred fifty-two million, two hundred forty-three thousand, three hundred fourteen".

Divisors: 1 2 17220676121657 34441352243314