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3444244321403 = 21798115800663
BaseRepresentation
bin110010000111101100111…
…101011001010001111011
3110012021012022100001100102
4302013230331121101323
5422412303021241103
611154133005030015
7503560404453554
oct62075475312173
913167168301312
103444244321403
111108772145656
1247762655530b
131bca38646c82
14bc9b921932b
155e8d555ae88
hex321ecf5947b

3444244321403 has 4 divisors (see below), whose sum is σ = 3444260340048. Its totient is φ = 3444228302760.

The previous prime is 3444244321367. The next prime is 3444244321409. The reversal of 3444244321403 is 3041234424443.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-3444244321403 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (3444244321409) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7682351 + ... + 8118312.

It is an arithmetic number, because the mean of its divisors is an integer number (861065085012).

Almost surely, 23444244321403 is an apocalyptic number.

3444244321403 is a deficient number, since it is larger than the sum of its proper divisors (16018645).

3444244321403 is a wasteful number, since it uses less digits than its factorization.

3444244321403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 16018644.

The product of its (nonzero) digits is 442368, while the sum is 38.

Adding to 3444244321403 its reverse (3041234424443), we get a palindrome (6485478745846).

The spelling of 3444244321403 in words is "three trillion, four hundred forty-four billion, two hundred forty-four million, three hundred twenty-one thousand, four hundred three".

Divisors: 1 217981 15800663 3444244321403