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3445211340042 = 231858730892661
BaseRepresentation
bin110010001000100110100…
…110010001110100001010
3110012100200200221200112120
4302020212212101310022
5422421243100340132
611154412551352110
7503623356131103
oct62104646216412
913170620850476
103445211340042
111109118a9200a
12477856382636
131bcb60aa7154
14bca6b81d3aa
155e9403c502c
hex32226991d0a

3445211340042 has 16 divisors (see below), whose sum is σ = 6890793615072. Its totient is φ = 1148341957520.

The previous prime is 3445211340029. The next prime is 3445211340071. The reversal of 3445211340042 is 2400431125443.

It is a junction number, because it is equal to n+sod(n) for n = 3445211339985 and 3445211340012.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 15334809 + ... + 15557852.

It is an arithmetic number, because the mean of its divisors is an integer number (430674600942).

Almost surely, 23445211340042 is an apocalyptic number.

3445211340042 is an abundant number, since it is smaller than the sum of its proper divisors (3445582275030).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

3445211340042 is a wasteful number, since it uses less digits than its factorization.

3445211340042 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 30911253.

The product of its (nonzero) digits is 46080, while the sum is 33.

Adding to 3445211340042 its reverse (2400431125443), we get a palindrome (5845642465485).

The spelling of 3445211340042 in words is "three trillion, four hundred forty-five billion, two hundred eleven million, three hundred forty thousand, forty-two".

Divisors: 1 2 3 6 18587 37174 55761 111522 30892661 61785322 92677983 185355966 574201890007 1148403780014 1722605670021 3445211340042