344832550141 has 4 divisors (see below), whose sum is σ = 345064138300. Its totient is φ = 344600961984.

The previous prime is 344832550079. The next prime is 344832550147. The reversal of 344832550141 is 141055238443.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 99556025625 + 245276524516 = 315525^2 + 495254^2 .

It is a cyclic number.

It is not a de Polignac number, because 344832550141 - 2¹⁵ = 344832517373 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 344832550094 and 344832550103.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (344832550147) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 115791846 + ... + 115794823.

It is an arithmetic number, because the mean of its divisors is an integer number (86266034575).

Almost surely, 2^344832550141 is an apocalyptic number.

It is an amenable number.

344832550141 is a deficient number, since it is larger than the sum of its proper divisors (231588159).

344832550141 is a wasteful number, since it uses less digits than its factorization.

344832550141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 231588158.

The product of its (nonzero) digits is 230400, while the sum is 40.

Adding to 344832550141 its reverse (141055238443), we get a palindrome (485887788584).

The spelling of 344832550141 in words is "three hundred forty-four billion, eight hundred thirty-two million, five hundred fifty thousand, one hundred forty-one".