Base | Representation |
---|---|
bin | 110010001110011111111… |
… | …000001000100101010101 |
3 | 110012222000211101022112101 |
4 | 302032133320020211111 |
5 | 423022224001000003 |
6 | 11201341022522101 |
7 | 504236255460250 |
oct | 62163770104525 |
9 | 13188024338471 |
10 | 3451541031253 |
11 | 1110876a26777 |
12 | 478b22136331 |
13 | 1c062c268273 |
14 | bd0ac330097 |
15 | 5ebb0e3411d |
hex | 3239fe08955 |
3451541031253 has 16 divisors (see below), whose sum is σ = 3965562779904. Its totient is φ = 2942762376960.
The previous prime is 3451541031251. The next prime is 3451541031319. The reversal of 3451541031253 is 3521301451543.
3451541031253 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 3451541031253 - 21 = 3451541031251 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3451541031251) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 5692168 + ... + 6269278.
It is an arithmetic number, because the mean of its divisors is an integer number (247847673744).
Almost surely, 23451541031253 is an apocalyptic number.
It is an amenable number.
3451541031253 is a deficient number, since it is larger than the sum of its proper divisors (514021748651).
3451541031253 is a wasteful number, since it uses less digits than its factorization.
3451541031253 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 581652.
The product of its (nonzero) digits is 108000, while the sum is 37.
Adding to 3451541031253 its reverse (3521301451543), we get a palindrome (6972842482796).
The spelling of 3451541031253 in words is "three trillion, four hundred fifty-one billion, five hundred forty-one million, thirty-one thousand, two hundred fifty-three".
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