Base | Representation |
---|---|
bin | 110010010000010101010… |
… | …111010111100111000111 |
3 | 110020011010012101200222122 |
4 | 302100111113113213013 |
5 | 423040243102403133 |
6 | 11202304354520155 |
7 | 504336151646414 |
oct | 62202527274707 |
9 | 13204105350878 |
10 | 3453512153543 |
11 | 111169863a061 |
12 | 47939229605b |
13 | 1c088474140a |
14 | bd21802d10b |
15 | 5ec78ee0498 |
hex | 324155d79c7 |
3453512153543 has 4 divisors (see below), whose sum is σ = 3454630159920. Its totient is φ = 3452394147168.
The previous prime is 3453512153491. The next prime is 3453512153647.
3453512153543 is nontrivially palindromic in base 10.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-3453512153543 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 3453512153494 and 3453512153503.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3453512158543) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 558998555 + ... + 559004732.
It is an arithmetic number, because the mean of its divisors is an integer number (863657539980).
Almost surely, 23453512153543 is an apocalyptic number.
3453512153543 is a deficient number, since it is larger than the sum of its proper divisors (1118006377).
3453512153543 is a wasteful number, since it uses less digits than its factorization.
3453512153543 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1118006376.
The product of its digits is 1620000, while the sum is 44.
The spelling of 3453512153543 in words is "three trillion, four hundred fifty-three billion, five hundred twelve million, one hundred fifty-three thousand, five hundred forty-three".
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