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3454012104543 = 32711213215717077
BaseRepresentation
bin110010010000110011001…
…010100001111101011111
3110020012102001010211211100
4302100303022201331133
5423042304044321133
611202430134324143
7504354432320460
oct62206312417537
913205361124740
103454012104543
111111924872700
124794b17b9653
131c09341aa100
14bd2645b0d67
155eca7d48e13
hex324332a1f5f

3454012104543 has 216 divisors, whose sum is σ = 6830148814944. Its totient is φ = 1645623682560.

The previous prime is 3454012104503. The next prime is 3454012104547.

3454012104543 is a `hidden beast` number, since 3 + 4 + 5 + 4 + 0 + 1 + 2 + 104 + 543 = 666.

3454012104543 is nontrivially palindromic in base 10.

It is not a de Polignac number, because 3454012104543 - 212 = 3454012100447 is a prime.

It is a super-2 number, since 2×34540121045432 (a number of 26 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 3454012104498 and 3454012104507.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (3454012104547) by changing a digit.

It is a polite number, since it can be written in 215 ways as a sum of consecutive naturals, for example, 202252521 + ... + 202269597.

Almost surely, 23454012104543 is an apocalyptic number.

3454012104543 is a gapful number since it is divisible by the number (33) formed by its first and last digit.

3454012104543 is a deficient number, since it is larger than the sum of its proper divisors (3376136710401).

3454012104543 is a wasteful number, since it uses less digits than its factorization.

3454012104543 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 17295 (or 17268 counting only the distinct ones).

The product of its (nonzero) digits is 115200, while the sum is 36.

The spelling of 3454012104543 in words is "three trillion, four hundred fifty-four billion, twelve million, one hundred four thousand, five hundred forty-three".