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34543311035 = 56908662207
BaseRepresentation
bin100000001010111100…
…010001100010111011
310022011101100000110012
4200022330101202323
51031221041423120
623511411012135
72332005204422
oct401274214273
9108141300405
1034543311035
1113716886942
12684059a04b
13334672451c
1419599ca2b9
15d729201c5
hex80af118bb

34543311035 has 4 divisors (see below), whose sum is σ = 41451973248. Its totient is φ = 27634648824.

The previous prime is 34543311029. The next prime is 34543311043. The reversal of 34543311035 is 53011334543.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 34543311035 - 28 = 34543310779 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 34543310992 and 34543311010.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3454331099 + ... + 3454331108.

It is an arithmetic number, because the mean of its divisors is an integer number (10362993312).

Almost surely, 234543311035 is an apocalyptic number.

34543311035 is a deficient number, since it is larger than the sum of its proper divisors (6908662213).

34543311035 is an equidigital number, since it uses as much as digits as its factorization.

34543311035 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6908662212.

The product of its (nonzero) digits is 32400, while the sum is 32.

Adding to 34543311035 its reverse (53011334543), we get a palindrome (87554645578).

The spelling of 34543311035 in words is "thirty-four billion, five hundred forty-three million, three hundred eleven thousand, thirty-five".

Divisors: 1 5 6908662207 34543311035