Base | Representation |
---|---|
bin | 100111010001110110111010… |
… | …1010010100101111100110001 |
3 | 1200022022200002221221200222020 |
4 | 1032203231311102211330301 |
5 | 330241201120113003213 |
6 | 3222453234314502053 |
7 | 132526461122100414 |
oct | 11643556522457461 |
9 | 1608280087850866 |
10 | 345502022000433 |
11 | a00a6648222391 |
12 | 32900734134929 |
13 | 11aa2915a8c75c |
14 | 614655c261b7b |
15 | 29e247918b923 |
hex | 13a3b754a5f31 |
345502022000433 has 64 divisors (see below), whose sum is σ = 482285221576704. Its totient is φ = 219757969800000.
The previous prime is 345502022000417. The next prime is 345502022000437. The reversal of 345502022000433 is 334000220205543.
It is not a de Polignac number, because 345502022000433 - 24 = 345502022000417 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 345502022000394 and 345502022000403.
It is not an unprimeable number, because it can be changed into a prime (345502022000437) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 5306321548 + ... + 5306386658.
It is an arithmetic number, because the mean of its divisors is an integer number (7535706587136).
Almost surely, 2345502022000433 is an apocalyptic number.
It is an amenable number.
345502022000433 is a deficient number, since it is larger than the sum of its proper divisors (136783199576271).
345502022000433 is a wasteful number, since it uses less digits than its factorization.
345502022000433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 67706.
The product of its (nonzero) digits is 86400, while the sum is 33.
Adding to 345502022000433 its reverse (334000220205543), we get a palindrome (679502242205976).
The spelling of 345502022000433 in words is "three hundred forty-five trillion, five hundred two billion, twenty-two million, four hundred thirty-three", and thus it is an aban number.
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