Base | Representation |
---|---|
bin | 110010010001110110100… |
… | …010110110011000111111 |
3 | 110020022022211021120210022 |
4 | 302101312202312120333 |
5 | 423102112443200101 |
6 | 11203134240002355 |
7 | 504424440061142 |
oct | 62216642663077 |
9 | 13208284246708 |
10 | 3455142553151 |
11 | 1112354994453 |
12 | 4797683003bb |
13 | 1c0a8445c003 |
14 | bd330798059 |
15 | 5ed221e6a1b |
hex | 324768b663f |
3455142553151 has 4 divisors (see below), whose sum is σ = 3513704291400. Its totient is φ = 3396580814904.
The previous prime is 3455142553147. The next prime is 3455142553153. The reversal of 3455142553151 is 1513552415543.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 3455142553151 - 22 = 3455142553147 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3455142553153) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 29280869036 + ... + 29280869153.
It is an arithmetic number, because the mean of its divisors is an integer number (878426072850).
Almost surely, 23455142553151 is an apocalyptic number.
3455142553151 is a deficient number, since it is larger than the sum of its proper divisors (58561738249).
3455142553151 is an equidigital number, since it uses as much as digits as its factorization.
3455142553151 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 58561738248.
The product of its digits is 900000, while the sum is 44.
Adding to 3455142553151 its reverse (1513552415543), we get a palindrome (4968694968694).
The spelling of 3455142553151 in words is "three trillion, four hundred fifty-five billion, one hundred forty-two million, five hundred fifty-three thousand, one hundred fifty-one".
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