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34555476103 = 149231915947
BaseRepresentation
bin100000001011101010…
…101011100010000111
310022012020020001210021
4200023222223202013
51031232200213403
623512523440011
72332213462201
oct401352534207
9108166201707
1034555476103
1113722735715
126844686007
1333490c36a5
14195b475771
15d73a248bd
hex80baab887

34555476103 has 4 divisors (see below), whose sum is σ = 34787392200. Its totient is φ = 34323560008.

The previous prime is 34555476041. The next prime is 34555476113. The reversal of 34555476103 is 30167455543.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 30167455543 = 107232813341.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-34555476103 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 34555476103.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (34555476113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 115957825 + ... + 115958122.

It is an arithmetic number, because the mean of its divisors is an integer number (8696848050).

Almost surely, 234555476103 is an apocalyptic number.

34555476103 is a deficient number, since it is larger than the sum of its proper divisors (231916097).

34555476103 is a wasteful number, since it uses less digits than its factorization.

34555476103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 231916096.

The product of its (nonzero) digits is 756000, while the sum is 43.

The spelling of 34555476103 in words is "thirty-four billion, five hundred fifty-five million, four hundred seventy-six thousand, one hundred three".

Divisors: 1 149 231915947 34555476103