347474113141 has 4 divisors (see below), whose sum is σ = 347498219232. Its totient is φ = 347450007052.

The previous prime is 347474113127. The next prime is 347474113163. The reversal of 347474113141 is 141311474743.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 141311474743 = 3727 ⋅37915609.

It is a cyclic number.

It is not a de Polignac number, because 347474113141 - 2¹⁷ = 347473982069 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 347474113094 and 347474113103.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (347474123141) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12031411 + ... + 12060256.

It is an arithmetic number, because the mean of its divisors is an integer number (86874554808).

Almost surely, 2^347474113141 is an apocalyptic number.

It is an amenable number.

347474113141 is a deficient number, since it is larger than the sum of its proper divisors (24106091).

347474113141 is a wasteful number, since it uses less digits than its factorization.

347474113141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 24106090.

The product of its digits is 112896, while the sum is 40.

Adding to 347474113141 its reverse (141311474743), we get a palindrome (488785587884).

The spelling of 347474113141 in words is "three hundred forty-seven billion, four hundred seventy-four million, one hundred thirteen thousand, one hundred forty-one".