Base | Representation |
---|---|
bin | 1111110011010011110000… |
… | …11101010101100000000001 |
3 | 11120000220110012212021000001 |
4 | 13321221320131111200001 |
5 | 14023304012413141201 |
6 | 201523052424000001 |
7 | 10214324265603316 |
oct | 771517035254001 |
9 | 146026405767001 |
10 | 34748306380801 |
11 | 1008774607a182 |
12 | 3a92555600001 |
13 | 165099c5c04a0 |
14 | 881b8141ad0d |
15 | 403d3ab8d301 |
hex | 1f9a78755801 |
34748306380801 has 32 divisors (see below), whose sum is σ = 37829980032768. Its totient is φ = 31727047100160.
The previous prime is 34748306380793. The next prime is 34748306380859. The reversal of 34748306380801 is 10808360384743.
It is a cyclic number.
It is not a de Polignac number, because 34748306380801 - 23 = 34748306380793 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (34748316380801) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1055104731 + ... + 1055137663.
It is an arithmetic number, because the mean of its divisors is an integer number (1182186876024).
Almost surely, 234748306380801 is an apocalyptic number.
It is an amenable number.
34748306380801 is a deficient number, since it is larger than the sum of its proper divisors (3081673651967).
34748306380801 is a wasteful number, since it uses less digits than its factorization.
34748306380801 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 35481.
The product of its (nonzero) digits is 9289728, while the sum is 55.
The spelling of 34748306380801 in words is "thirty-four trillion, seven hundred forty-eight billion, three hundred six million, three hundred eighty thousand, eight hundred one".
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