Base | Representation |
---|---|
bin | 110010101011111001001… |
… | …010101001011010100101 |
3 | 110022222111111100111111110 |
4 | 302223321022221122211 |
5 | 424031344034440441 |
6 | 11224041003055233 |
7 | 506434363015605 |
oct | 62537112513245 |
9 | 13288444314443 |
10 | 3483103827621 |
11 | 11231a3340850 |
12 | 483070511519 |
13 | 1c35bc33b332 |
14 | c0824146c05 |
15 | 6090bd5db16 |
hex | 32af92a96a5 |
3483103827621 has 16 divisors (see below), whose sum is σ = 5066523021888. Its totient is φ = 2110892774400.
The previous prime is 3483103827601. The next prime is 3483103827649. The reversal of 3483103827621 is 1267283013843.
It is not a de Polignac number, because 3483103827621 - 218 = 3483103565477 is a prime.
It is a super-3 number, since 3×34831038276213 (a number of 39 digits) contains 333 as substring.
It is a Curzon number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3483103827601) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1082556 + ... + 2852741.
It is an arithmetic number, because the mean of its divisors is an integer number (316657688868).
Almost surely, 23483103827621 is an apocalyptic number.
It is an amenable number.
3483103827621 is a deficient number, since it is larger than the sum of its proper divisors (1583419194267).
3483103827621 is a wasteful number, since it uses less digits than its factorization.
3483103827621 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3962132.
The product of its (nonzero) digits is 1161216, while the sum is 48.
The spelling of 3483103827621 in words is "three trillion, four hundred eighty-three billion, one hundred three million, eight hundred twenty-seven thousand, six hundred twenty-one".
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