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3483127103904 = 25347715474943
BaseRepresentation
bin110010101011111010100…
…011011100000110100000
3110022222120010011001120000
4302223322203130012200
5424031421014311104
611224043154020000
7506435064611520
oct62537243340640
913288503131500
103483127103904
111123205499648
12483078277600
131c35c40caa96
14c0827285680
156090de0a639
hex32afa8dc1a0

3483127103904 has 480 divisors, whose sum is σ = 11896177176576. Its totient is φ = 979170716160.

The previous prime is 3483127103903. The next prime is 3483127103917. The reversal of 3483127103904 is 4093017213843.

3483127103904 is a `hidden beast` number, since 3 + 483 + 12 + 71 + 0 + 3 + 90 + 4 = 666.

It is a self number, because there is not a number n which added to its sum of digits gives 3483127103904.

It is not an unprimeable number, because it can be changed into a prime (3483127103903) by changing a digit.

It is a polite number, since it can be written in 79 ways as a sum of consecutive naturals, for example, 704656057 + ... + 704660999.

Almost surely, 23483127103904 is an apocalyptic number.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 3483127103904, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (5948088588288).

3483127103904 is an abundant number, since it is smaller than the sum of its proper divisors (8413050072672).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

3483127103904 is a wasteful number, since it uses less digits than its factorization.

3483127103904 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5590 (or 5573 counting only the distinct ones).

The product of its (nonzero) digits is 435456, while the sum is 45.

The spelling of 3483127103904 in words is "three trillion, four hundred eighty-three billion, one hundred twenty-seven million, one hundred three thousand, nine hundred four".