Base | Representation |
---|---|
bin | 110010101100001000101… |
… | …111110101100000001111 |
3 | 110100000011201020100121020 |
4 | 302230020233311200033 |
5 | 424032413000002303 |
6 | 11224122542005223 |
7 | 506444015650434 |
oct | 62541057654017 |
9 | 13300151210536 |
10 | 3483365234703 |
11 | 1123317955862 |
12 | 483123b76813 |
13 | 1c3631545b93 |
14 | c084ab51b8b |
15 | 60924c97a53 |
hex | 32b08bf580f |
3483365234703 has 8 divisors (see below), whose sum is σ = 4646440917168. Its totient is φ = 2321266521024.
The previous prime is 3483365234683. The next prime is 3483365234719. The reversal of 3483365234703 is 3074325633843.
3483365234703 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 3483365234703 - 29 = 3483365234191 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3483365234743) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 244233876 + ... + 244248137.
It is an arithmetic number, because the mean of its divisors is an integer number (580805114646).
Almost surely, 23483365234703 is an apocalyptic number.
3483365234703 is a deficient number, since it is larger than the sum of its proper divisors (1163075682465).
3483365234703 is a wasteful number, since it uses less digits than its factorization.
3483365234703 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 488484393.
The product of its (nonzero) digits is 13063680, while the sum is 51.
The spelling of 3483365234703 in words is "three trillion, four hundred eighty-three billion, three hundred sixty-five million, two hundred thirty-four thousand, seven hundred three".
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