3483365541303 has 4 divisors (see below), whose sum is σ = 4644487388408. Its totient is φ = 2322243694200.

The previous prime is 3483365541277. The next prime is 3483365541311. The reversal of 3483365541303 is 3031455633843.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 3483365541303 - 2¹² = 3483365537207 is a prime.

It is a super-3 number, since 3×3483365541303³ (a number of 39 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (3483365541373) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 580560923548 + ... + 580560923553.

It is an arithmetic number, because the mean of its divisors is an integer number (1161121847102).

Almost surely, 2^{3483365541303} is an apocalyptic number.

3483365541303 is a deficient number, since it is larger than the sum of its proper divisors (1161121847105).

3483365541303 is a wasteful number, since it uses less digits than its factorization.

3483365541303 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1161121847104.

The product of its (nonzero) digits is 4665600, while the sum is 48.

The spelling of 3483365541303 in words is "three trillion, four hundred eighty-three billion, three hundred sixty-five million, five hundred forty-one thousand, three hundred three".