3483993843 has 32 divisors (see below), whose sum is σ = 5927059200. Its totient is φ = 2000376000.

The previous prime is 3483993829. The next prime is 3483993853.

3483993843 is a `hidden beast` number, since 3 + 483 + 99 + 38 + 43 = 666.

3483993843 is nontrivially palindromic in base 10.

It is not a de Polignac number, because 3483993843 - 2⁴ = 3483993827 is a prime.

It is a super-3 number, since 3×3483993843³ (a number of 30 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 3483993843.

It is not an unprimeable number, because it can be changed into a prime (3483993823) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 303058 + ... + 314343.

It is an arithmetic number, because the mean of its divisors is an integer number (185220600).

Almost surely, 2^3483993843 is an apocalyptic number.

3483993843 is a gapful number since it is divisible by the number (33) formed by its first and last digit.

3483993843 is a deficient number, since it is larger than the sum of its proper divisors (2443065357).

3483993843 is a wasteful number, since it uses less digits than its factorization.

3483993843 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 617440 (or 617434 counting only the distinct ones).

The product of its digits is 6718464, while the sum is 54.

The square root of 3483993843 is about 59025.3660979752. The cubic root of 3483993843 is about 1515.9764668632.

The spelling of 3483993843 in words is "three billion, four hundred eighty-three million, nine hundred ninety-three thousand, eight hundred forty-three".