349351153943 has 16 divisors (see below), whose sum is σ = 403800297984. Its totient is φ = 298708824960.

The previous prime is 349351153939. The next prime is 349351154083.

349351153943 is nontrivially palindromic in base 10.

It is a cyclic number.

It is not a de Polignac number, because 349351153943 - 2² = 349351153939 is a prime.

It is a super-2 number, since 2×349351153943² (a number of 24 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 349351153891 and 349351153900.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (349351153913) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 350105 + ... + 906242.

It is an arithmetic number, because the mean of its divisors is an integer number (25237518624).

Almost surely, 2^349351153943 is an apocalyptic number.

349351153943 is a deficient number, since it is larger than the sum of its proper divisors (54449144041).

349351153943 is a wasteful number, since it uses less digits than its factorization.

349351153943 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1257862.

The product of its digits is 2624400, while the sum is 50.

The spelling of 349351153943 in words is "three hundred forty-nine billion, three hundred fifty-one million, one hundred fifty-three thousand, nine hundred forty-three".