Base | Representation |
---|---|
bin | 110010111011111101011… |
… | …010110001110000000001 |
3 | 110101122000202112120221020 |
4 | 302323331122301300001 |
5 | 424322211342042423 |
6 | 11240012500220053 |
7 | 510615026605350 |
oct | 62737532616001 |
9 | 13348022476836 |
10 | 3500355034113 |
11 | 112a5461875a3 |
12 | 48648599a629 |
13 | 1c510b3a7322 |
14 | c15bd337997 |
15 | 610bb6074e3 |
hex | 32efd6b1c01 |
3500355034113 has 8 divisors (see below), whose sum is σ = 5333874337728. Its totient is φ = 2000202876624.
The previous prime is 3500355034097. The next prime is 3500355034249. The reversal of 3500355034113 is 3114305530053.
It is a happy number.
3500355034113 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 3500355034113 - 24 = 3500355034097 is a prime.
It is not an unprimeable number, because it can be changed into a prime (3500355033113) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 83341786506 + ... + 83341786547.
It is an arithmetic number, because the mean of its divisors is an integer number (666734292216).
Almost surely, 23500355034113 is an apocalyptic number.
It is an amenable number.
3500355034113 is a deficient number, since it is larger than the sum of its proper divisors (1833519303615).
3500355034113 is a wasteful number, since it uses less digits than its factorization.
3500355034113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 166683573063.
The product of its (nonzero) digits is 40500, while the sum is 33.
The spelling of 3500355034113 in words is "three trillion, five hundred billion, three hundred fifty-five million, thirty-four thousand, one hundred thirteen".
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