350040114301 has 4 divisors (see below), whose sum is σ = 362110463100. Its totient is φ = 337969765504.

The previous prime is 350040114299. The next prime is 350040114311. The reversal of 350040114301 is 103411040053.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 84186442201 + 265853672100 = 290149^2 + 515610^2 .

It is a cyclic number.

It is not a de Polignac number, because 350040114301 - 2¹ = 350040114299 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (350040114311) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6035174356 + ... + 6035174413.

It is an arithmetic number, because the mean of its divisors is an integer number (90527615775).

Almost surely, 2^350040114301 is an apocalyptic number.

It is an amenable number.

350040114301 is a deficient number, since it is larger than the sum of its proper divisors (12070348799).

350040114301 is a wasteful number, since it uses less digits than its factorization.

350040114301 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12070348798.

The product of its (nonzero) digits is 720, while the sum is 22.

Adding to 350040114301 its reverse (103411040053), we get a palindrome (453451154354).

The spelling of 350040114301 in words is "three hundred fifty billion, forty million, one hundred fourteen thousand, three hundred one".