Base | Representation |
---|---|
bin | 1010001100110001000… |
… | …01101101000011101001 |
3 | 1020111120112222210021211 |
4 | 11012120201231003221 |
5 | 21220211014314423 |
6 | 424554540033121 |
7 | 34214340045043 |
oct | 5063041550351 |
9 | 1214515883254 |
10 | 350451323113 |
11 | 1256976aa061 |
12 | 57b055327a1 |
13 | 2708023c618 |
14 | 12d67796a93 |
15 | 91b19a410d |
hex | 519886d0e9 |
350451323113 has 4 divisors (see below), whose sum is σ = 350452601668. Its totient is φ = 350450044560.
The previous prime is 350451323029. The next prime is 350451323129. The reversal of 350451323113 is 311323154053.
It is a happy number.
It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.
It can be written as a sum of positive squares in 2 ways, for example, as 257614108249 + 92837214864 = 507557^2 + 304692^2 .
It is a cyclic number.
It is not a de Polignac number, because 350451323113 - 217 = 350451192041 is a prime.
It is a super-2 number, since 2×3504513231132 (a number of 24 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (350451323813) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 42306 + ... + 838267.
It is an arithmetic number, because the mean of its divisors is an integer number (87613150417).
Almost surely, 2350451323113 is an apocalyptic number.
It is an amenable number.
350451323113 is a deficient number, since it is larger than the sum of its proper divisors (1278555).
350451323113 is an equidigital number, since it uses as much as digits as its factorization.
350451323113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1278554.
The product of its (nonzero) digits is 16200, while the sum is 31.
Adding to 350451323113 its reverse (311323154053), we get a palindrome (661774477166).
The spelling of 350451323113 in words is "three hundred fifty billion, four hundred fifty-one million, three hundred twenty-three thousand, one hundred thirteen".
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