351049247999 has 4 divisors (see below), whose sum is σ = 351056779800. Its totient is φ = 351041716200.

The previous prime is 351049247921. The next prime is 351049248049. The reversal of 351049247999 is 999742940153.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-351049247999 is a prime.

It is a super-3 number, since 3×351049247999³ (a number of 36 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (351049217999) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3695549 + ... + 3789350.

It is an arithmetic number, because the mean of its divisors is an integer number (87764194950).

Almost surely, 2^351049247999 is an apocalyptic number.

351049247999 is a deficient number, since it is larger than the sum of its proper divisors (7531801).

351049247999 is an equidigital number, since it uses as much as digits as its factorization.

351049247999 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7531800.

The product of its (nonzero) digits is 22044960, while the sum is 62.

The spelling of 351049247999 in words is "three hundred fifty-one billion, forty-nine million, two hundred forty-seven thousand, nine hundred ninety-nine".