Base | Representation |
---|---|
bin | 100111111011011010110010… |
… | …0001110010000100110001001 |
3 | 1201001112201211110121100220002 |
4 | 1033312311210032100212021 |
5 | 332013242324242433101 |
6 | 3242545300434212345 |
7 | 133656243242235635 |
oct | 11766654416204611 |
9 | 1631481743540802 |
10 | 351214042155401 |
11 | a19a9047735907 |
12 | 334837741240b5 |
13 | 120c845a691289 |
14 | 62a2bc9495dc5 |
15 | 2a90d3ad67d6b |
hex | 13f6d64390989 |
351214042155401 has 16 divisors (see below), whose sum is σ = 388295570371968. Its totient is φ = 315975941740800.
The previous prime is 351214042155377. The next prime is 351214042155407. The reversal of 351214042155401 is 104551240412153.
It is a de Polignac number, because none of the positive numbers 2k-351214042155401 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (351214042155407) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 292753970 + ... + 293951211.
It is an arithmetic number, because the mean of its divisors is an integer number (24268473148248).
Almost surely, 2351214042155401 is an apocalyptic number.
It is an amenable number.
351214042155401 is a deficient number, since it is larger than the sum of its proper divisors (37081528216567).
351214042155401 is a wasteful number, since it uses less digits than its factorization.
351214042155401 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 586706752.
The product of its (nonzero) digits is 96000, while the sum is 38.
Adding to 351214042155401 its reverse (104551240412153), we get a palindrome (455765282567554).
The spelling of 351214042155401 in words is "three hundred fifty-one trillion, two hundred fourteen billion, forty-two million, one hundred fifty-five thousand, four hundred one".
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