35124341413 has 4 divisors (see below), whose sum is σ = 40142104480. Its totient is φ = 30106578348.

The previous prime is 35124341387. The next prime is 35124341437. The reversal of 35124341413 is 31414342153.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31414342153 = 1627 ⋅19308139.

It is not a de Polignac number, because 35124341413 - 2⁵ = 35124341381 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (35124341453) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2508881523 + ... + 2508881536.

It is an arithmetic number, because the mean of its divisors is an integer number (10035526120).

Almost surely, 2^35124341413 is an apocalyptic number.

It is an amenable number.

35124341413 is a deficient number, since it is larger than the sum of its proper divisors (5017763067).

35124341413 is an equidigital number, since it uses as much as digits as its factorization.

35124341413 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5017763066.

The product of its digits is 17280, while the sum is 31.

Adding to 35124341413 its reverse (31414342153), we get a palindrome (66538683566).

The spelling of 35124341413 in words is "thirty-five billion, one hundred twenty-four million, three hundred forty-one thousand, four hundred thirteen".