3512503252145 has 4 divisors (see below), whose sum is σ = 4215003902580. Its totient is φ = 2810002601712.

The previous prime is 3512503252129. The next prime is 3512503252187. The reversal of 3512503252145 is 5412523052153.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 1144487017249 + 2368016234896 = 1069807^2 + 1538836^2 .

It is a cyclic number.

It is not a de Polignac number, because 3512503252145 - 2⁴ = 3512503252129 is a prime.

It is a super-3 number, since 3×3512503252145³ (a number of 39 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 3512503252099 and 3512503252108.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 351250325210 + ... + 351250325219.

It is an arithmetic number, because the mean of its divisors is an integer number (1053750975645).

Almost surely, 2^{3512503252145} is an apocalyptic number.

It is an amenable number.

3512503252145 is a deficient number, since it is larger than the sum of its proper divisors (702500650435).

3512503252145 is an equidigital number, since it uses as much as digits as its factorization.

3512503252145 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 702500650434.

The product of its (nonzero) digits is 180000, while the sum is 38.

The spelling of 3512503252145 in words is "three trillion, five hundred twelve billion, five hundred three million, two hundred fifty-two thousand, one hundred forty-five".