Base | Representation |
---|---|
bin | 1111111110010010001101… |
… | …10001110111000000000001 |
3 | 11121100221212121112012110001 |
4 | 13333021012301313000001 |
5 | 14100443340041202040 |
6 | 202412222204240001 |
7 | 10253504620633201 |
oct | 777110661670001 |
9 | 147327777465401 |
10 | 35125430022145 |
11 | 1021267a590741 |
12 | 3b33663540001 |
13 | 167a41066cb18 |
14 | 8961192b8401 |
15 | 40da5e04b59a |
hex | 1ff246c77001 |
35125430022145 has 8 divisors (see below), whose sum is σ = 42159387980160. Its totient is φ = 28094429382000.
The previous prime is 35125430022121. The next prime is 35125430022181. The reversal of 35125430022145 is 54122003452153.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 35125430022145 - 213 = 35125430013953 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 739303335 + ... + 739350844.
It is an arithmetic number, because the mean of its divisors is an integer number (5269923497520).
Almost surely, 235125430022145 is an apocalyptic number.
It is an amenable number.
35125430022145 is a deficient number, since it is larger than the sum of its proper divisors (7033957958015).
35125430022145 is a wasteful number, since it uses less digits than its factorization.
35125430022145 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1478658935.
The product of its (nonzero) digits is 144000, while the sum is 37.
Adding to 35125430022145 its reverse (54122003452153), we get a palindrome (89247433474298).
The spelling of 35125430022145 in words is "thirty-five trillion, one hundred twenty-five billion, four hundred thirty million, twenty-two thousand, one hundred forty-five".
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