35130040441 has 8 divisors (see below), whose sum is σ = 36595961600. Its totient is φ = 33684912720.

The previous prime is 35130040409. The next prime is 35130040447. The reversal of 35130040441 is 14404003153.

35130040441 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 35130040441 - 2⁵ = 35130040409 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (35130040447) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5194911 + ... + 5201668.

It is an arithmetic number, because the mean of its divisors is an integer number (4574495200).

Almost surely, 2^35130040441 is an apocalyptic number.

35130040441 is a gapful number since it is divisible by the number (31) formed by its first and last digit.

It is an amenable number.

35130040441 is a deficient number, since it is larger than the sum of its proper divisors (1465921159).

35130040441 is a wasteful number, since it uses less digits than its factorization.

35130040441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10396719.

The product of its (nonzero) digits is 2880, while the sum is 25.

Adding to 35130040441 its reverse (14404003153), we get a palindrome (49534043594).

The spelling of 35130040441 in words is "thirty-five billion, one hundred thirty million, forty thousand, four hundred forty-one".