35131222213153 has 4 divisors (see below), whose sum is σ = 38324969687088. Its totient is φ = 31937474739220.

The previous prime is 35131222213147. The next prime is 35131222213181.

35131222213153 is nontrivially palindromic in base 10.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 35131222213153 - 2⁹ = 35131222212641 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (35131222213103) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1596873736951 + ... + 1596873736972.

It is an arithmetic number, because the mean of its divisors is an integer number (9581242421772).

Almost surely, 2^{35131222213153} is an apocalyptic number.

It is an amenable number.

35131222213153 is a deficient number, since it is larger than the sum of its proper divisors (3193747473935).

35131222213153 is a wasteful number, since it uses less digits than its factorization.

35131222213153 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3193747473934.

The product of its digits is 32400, while the sum is 34.

It can be divided in two parts, 3513122 and 2213153, that added together give a palindrome (5726275).

The spelling of 35131222213153 in words is "thirty-five trillion, one hundred thirty-one billion, two hundred twenty-two million, two hundred thirteen thousand, one hundred fifty-three".