35146011064153 has 4 divisors (see below), whose sum is σ = 38341102979088. Its totient is φ = 31950919149220.

The previous prime is 35146011064139. The next prime is 35146011064159.

It is a happy number.

35146011064153 is nontrivially palindromic in base 10.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 35146011064153 - 2⁹ = 35146011063641 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (35146011064159) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1597545957451 + ... + 1597545957472.

It is an arithmetic number, because the mean of its divisors is an integer number (9585275744772).

Almost surely, 2^{35146011064153} is an apocalyptic number.

It is an amenable number.

35146011064153 is a deficient number, since it is larger than the sum of its proper divisors (3195091914935).

35146011064153 is a wasteful number, since it uses less digits than its factorization.

35146011064153 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3195091914934.

The product of its (nonzero) digits is 129600, while the sum is 40.

It can be divided in two parts, 3514601 and 1064153, that added together give a palindrome (4578754).

The spelling of 35146011064153 in words is "thirty-five trillion, one hundred forty-six billion, eleven million, sixty-four thousand, one hundred fifty-three".