35148450253 has 4 divisors (see below), whose sum is σ = 40169657440. Its totient is φ = 30127243068.

The previous prime is 35148450251. The next prime is 35148450257. The reversal of 35148450253 is 35205484153.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 35205484153 = 7 ⋅5029354879.

It is a cyclic number.

It is not a de Polignac number, because 35148450253 - 2¹ = 35148450251 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (35148450251) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2510603583 + ... + 2510603596.

It is an arithmetic number, because the mean of its divisors is an integer number (10042414360).

Almost surely, 2^35148450253 is an apocalyptic number.

It is an amenable number.

35148450253 is a deficient number, since it is larger than the sum of its proper divisors (5021207187).

35148450253 is an equidigital number, since it uses as much as digits as its factorization.

35148450253 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5021207186.

The product of its (nonzero) digits is 288000, while the sum is 40.

The spelling of 35148450253 in words is "thirty-five billion, one hundred forty-eight million, four hundred fifty thousand, two hundred fifty-three".