352013113 has 4 divisors (see below), whose sum is σ = 354700368. Its totient is φ = 349325860.

The previous prime is 352013111. The next prime is 352013117. The reversal of 352013113 is 311310253.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 311310253 = 41 ⋅7592933.

It is a cyclic number.

It is not a de Polignac number, because 352013113 - 2¹ = 352013111 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (352013111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1343431 + ... + 1343692.

It is an arithmetic number, because the mean of its divisors is an integer number (88675092).

Almost surely, 2^352013113 is an apocalyptic number.

It is an amenable number.

352013113 is a deficient number, since it is larger than the sum of its proper divisors (2687255).

352013113 is a wasteful number, since it uses less digits than its factorization.

352013113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2687254.

The product of its (nonzero) digits is 270, while the sum is 19.

The square root of 352013113 is about 18762.0124986634. The cubic root of 352013113 is about 706.0784346567.

Adding to 352013113 its reverse (311310253), we get a palindrome (663323366).

The spelling of 352013113 in words is "three hundred fifty-two million, thirteen thousand, one hundred thirteen".