3520131354443 has 16 divisors (see below), whose sum is σ = 3847032324576. Its totient is φ = 3194382896640.

The previous prime is 3520131354427. The next prime is 3520131354451. The reversal of 3520131354443 is 3444531310253.

It is a cyclic number.

It is not a de Polignac number, because 3520131354443 - 2⁴ = 3520131354427 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 3520131354397 and 3520131354406.

It is not an unprimeable number, because it can be changed into a prime (3520131354463) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 16313405 + ... + 16527777.

It is an arithmetic number, because the mean of its divisors is an integer number (240439520286).

Almost surely, 2^{3520131354443} is an apocalyptic number.

3520131354443 is a deficient number, since it is larger than the sum of its proper divisors (326900970133).

3520131354443 is a wasteful number, since it uses less digits than its factorization.

3520131354443 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 217054.

The product of its (nonzero) digits is 259200, while the sum is 38.

Adding to 3520131354443 its reverse (3444531310253), we get a palindrome (6964662664696).

The spelling of 3520131354443 in words is "three trillion, five hundred twenty billion, one hundred thirty-one million, three hundred fifty-four thousand, four hundred forty-three".