Base | Representation |
---|---|
bin | 1000011001010… |
… | …0101101101101 |
3 | 2110020221222101 |
4 | 2012110231231 |
5 | 33003242031 |
6 | 3254415101 |
7 | 605204206 |
oct | 206245555 |
9 | 73227871 |
10 | 35212141 |
11 | 18970448 |
12 | b961491 |
13 | 73ab4b3 |
14 | 49685ad |
15 | 3158361 |
hex | 2194b6d |
35212141 has 4 divisors (see below), whose sum is σ = 36031072. Its totient is φ = 34393212.
The previous prime is 35212139. The next prime is 35212157. The reversal of 35212141 is 14121253.
35212141 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 14121253 = 971 ⋅14543.
It is a cyclic number.
It is not a de Polignac number, because 35212141 - 21 = 35212139 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (35212171) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 409401 + ... + 409486.
It is an arithmetic number, because the mean of its divisors is an integer number (9007768).
Almost surely, 235212141 is an apocalyptic number.
It is an amenable number.
35212141 is a deficient number, since it is larger than the sum of its proper divisors (818931).
35212141 is an equidigital number, since it uses as much as digits as its factorization.
35212141 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 818930.
The product of its digits is 240, while the sum is 19.
The square root of 35212141 is about 5933.9818840303. The cubic root of 35212141 is about 327.7661833770.
Adding to 35212141 its reverse (14121253), we get a palindrome (49333394).
It can be divided in two parts, 35212 and 141, that added together give a palindrome (35353).
The spelling of 35212141 in words is "thirty-five million, two hundred twelve thousand, one hundred forty-one".
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