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352140433 = 1937500911
BaseRepresentation
bin10100111111010…
…011110010010001
3220112121120212021
4110333103302101
51210121443213
654535331441
711504100331
oct2477236221
9815546767
10352140433
11170857357
1299b20b81
1357c55528
1434aa70c1
1520dacd8d
hex14fd3c91

352140433 has 8 divisors (see below), whose sum is σ = 380693120. Its totient is φ = 324589680.

The previous prime is 352140421. The next prime is 352140461. The reversal of 352140433 is 334041253.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-352140433 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 352140398 and 352140407.

It is not an unprimeable number, because it can be changed into a prime (352140493) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 249753 + ... + 251158.

It is an arithmetic number, because the mean of its divisors is an integer number (47586640).

Almost surely, 2352140433 is an apocalyptic number.

It is an amenable number.

352140433 is a deficient number, since it is larger than the sum of its proper divisors (28552687).

352140433 is a wasteful number, since it uses less digits than its factorization.

352140433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 500967.

The product of its (nonzero) digits is 4320, while the sum is 25.

The square root of 352140433 is about 18765.4052181135. The cubic root of 352140433 is about 706.1635518173.

Adding to 352140433 its reverse (334041253), we get a palindrome (686181686).

The spelling of 352140433 in words is "three hundred fifty-two million, one hundred forty thousand, four hundred thirty-three".

Divisors: 1 19 37 703 500911 9517309 18533707 352140433