Base | Representation |
---|---|
bin | 10100111111010… |
… | …011110010010001 |
3 | 220112121120212021 |
4 | 110333103302101 |
5 | 1210121443213 |
6 | 54535331441 |
7 | 11504100331 |
oct | 2477236221 |
9 | 815546767 |
10 | 352140433 |
11 | 170857357 |
12 | 99b20b81 |
13 | 57c55528 |
14 | 34aa70c1 |
15 | 20dacd8d |
hex | 14fd3c91 |
352140433 has 8 divisors (see below), whose sum is σ = 380693120. Its totient is φ = 324589680.
The previous prime is 352140421. The next prime is 352140461. The reversal of 352140433 is 334041253.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-352140433 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 352140398 and 352140407.
It is not an unprimeable number, because it can be changed into a prime (352140493) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 249753 + ... + 251158.
It is an arithmetic number, because the mean of its divisors is an integer number (47586640).
Almost surely, 2352140433 is an apocalyptic number.
It is an amenable number.
352140433 is a deficient number, since it is larger than the sum of its proper divisors (28552687).
352140433 is a wasteful number, since it uses less digits than its factorization.
352140433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 500967.
The product of its (nonzero) digits is 4320, while the sum is 25.
The square root of 352140433 is about 18765.4052181135. The cubic root of 352140433 is about 706.1635518173.
Adding to 352140433 its reverse (334041253), we get a palindrome (686181686).
The spelling of 352140433 in words is "three hundred fifty-two million, one hundred forty thousand, four hundred thirty-three".
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