35231133113253 has 72 divisors (see below), whose sum is σ = 65206503251136. Its totient is φ = 18124198848000.

The previous prime is 35231133113203. The next prime is 35231133113263.

35231133113253 is a `hidden beast` number, since 3 + 5 + 2 + 3 + 1 + 13 + 311 + 325 + 3 = 666.

35231133113253 is nontrivially palindromic in base 10.

It is not a de Polignac number, because 35231133113253 - 2⁸ = 35231133112997 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (35231133113203) by changing a digit.

It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 34755948 + ... + 35755253.

It is an arithmetic number, because the mean of its divisors is an integer number (905645878488).

Almost surely, 2^{35231133113253} is an apocalyptic number.

35231133113253 is a gapful number since it is divisible by the number (33) formed by its first and last digit.

It is an amenable number.

35231133113253 is a deficient number, since it is larger than the sum of its proper divisors (29975370137883).

35231133113253 is a wasteful number, since it uses less digits than its factorization.

35231133113253 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 70511335 (or 70511325 counting only the distinct ones).

The product of its digits is 72900, while the sum is 36.

It can be divided in two parts, 3523113 and 3113253, that added together give a palindrome (6636366).

The spelling of 35231133113253 in words is "thirty-five trillion, two hundred thirty-one billion, one hundred thirty-three million, one hundred thirteen thousand, two hundred fifty-three".