35400113 has 4 divisors (see below), whose sum is σ = 40457280. Its totient is φ = 30342948.

The previous prime is 35400091. The next prime is 35400121. The reversal of 35400113 is 31100453.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31100453 = 53 ⋅586801.

It is a cyclic number.

It is not a de Polignac number, because 35400113 - 2⁶ = 35400049 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 35400091 and 35400100.

It is not an unprimeable number, because it can be changed into a prime (35400143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2528573 + ... + 2528586.

It is an arithmetic number, because the mean of its divisors is an integer number (10114320).

Almost surely, 2^35400113 is an apocalyptic number.

It is an amenable number.

35400113 is a deficient number, since it is larger than the sum of its proper divisors (5057167).

35400113 is an equidigital number, since it uses as much as digits as its factorization.

35400113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5057166.

The product of its (nonzero) digits is 180, while the sum is 17.

The square root of 35400113 is about 5949.7994083834. The cubic root of 35400113 is about 328.3483836768.

Adding to 35400113 its reverse (31100453), we get a palindrome (66500566).

The spelling of 35400113 in words is "thirty-five million, four hundred thousand, one hundred thirteen".