35400154331041 has 4 divisors (see below), whose sum is σ = 37482516350532. Its totient is φ = 33317792311552.

The previous prime is 35400154330991. The next prime is 35400154331089. The reversal of 35400154331041 is 14013345100453.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 22324727259025 + 13075427072016 = 4724905^2 + 3615996^2 .

It is a cyclic number.

It is not a de Polignac number, because 35400154331041 - 2¹¹ = 35400154328993 is a prime.

It is a super-2 number, since 2×35400154331041² (a number of 28 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 35400154330988 and 35400154331006.

It is not an unprimeable number, because it can be changed into a prime (35400154331441) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1041181009720 + ... + 1041181009753.

It is an arithmetic number, because the mean of its divisors is an integer number (9370629087633).

Almost surely, 2^{35400154331041} is an apocalyptic number.

It is an amenable number.

35400154331041 is a deficient number, since it is larger than the sum of its proper divisors (2082362019491).

35400154331041 is a wasteful number, since it uses less digits than its factorization.

35400154331041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2082362019490.

The product of its (nonzero) digits is 43200, while the sum is 34.

Adding to 35400154331041 its reverse (14013345100453), we get a palindrome (49413499431494).

The spelling of 35400154331041 in words is "thirty-five trillion, four hundred billion, one hundred fifty-four million, three hundred thirty-one thousand, forty-one".