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3540023065045 = 517311913352783
BaseRepresentation
bin110011100000111001110…
…100010011100111010101
3110112102102021221100111001
4303200321310103213111
5430444431401040140
611310133015543301
7513521033400325
oct63407164234725
913472367840431
103540023065045
111145351806335
124920b668ab31
131c8a9074778c
14c34a37ad285
156213ddb7e9a
hex33839d139d5

3540023065045 has 16 divisors (see below), whose sum is σ = 4499354096640. Its totient is φ = 2664574353664.

The previous prime is 3540023065031. The next prime is 3540023065067. The reversal of 3540023065045 is 5405603200453.

It is a cyclic number.

It is not a de Polignac number, because 3540023065045 - 215 = 3540023032277 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 3540023064995 and 3540023065013.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 6411277 + ... + 6941506.

It is an arithmetic number, because the mean of its divisors is an integer number (281209631040).

Almost surely, 23540023065045 is an apocalyptic number.

It is an amenable number.

3540023065045 is a deficient number, since it is larger than the sum of its proper divisors (959331031595).

3540023065045 is a wasteful number, since it uses less digits than its factorization.

3540023065045 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 13355924.

The product of its (nonzero) digits is 216000, while the sum is 37.

Adding to 3540023065045 its reverse (5405603200453), we get a palindrome (8945626265498).

The spelling of 3540023065045 in words is "three trillion, five hundred forty billion, twenty-three million, sixty-five thousand, forty-five".

Divisors: 1 5 17 85 3119 15595 53023 265115 13352783 66763915 226997311 1134986555 41647330177 208236650885 708004613009 3540023065045