3540130441213 has 4 divisors (see below), whose sum is σ = 3540147535260. Its totient is φ = 3540113347168.

The previous prime is 3540130441201. The next prime is 3540130441241. The reversal of 3540130441213 is 3121440310453.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 156785905444 + 3383344535769 = 395962^2 + 1839387^2 .

It is a cyclic number.

It is not a de Polignac number, because 3540130441213 - 2²¹ = 3540128344061 is a prime.

It is a super-2 number, since 2×3540130441213² (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (3540130441013) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8232520 + ... + 8651857.

It is an arithmetic number, because the mean of its divisors is an integer number (885036883815).

Almost surely, 2^{3540130441213} is an apocalyptic number.

It is an amenable number.

3540130441213 is a deficient number, since it is larger than the sum of its proper divisors (17094047).

3540130441213 is a wasteful number, since it uses less digits than its factorization.

3540130441213 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 17094046.

The product of its (nonzero) digits is 17280, while the sum is 31.

Adding to 3540130441213 its reverse (3121440310453), we get a palindrome (6661570751666).

The spelling of 3540130441213 in words is "three trillion, five hundred forty billion, one hundred thirty million, four hundred forty-one thousand, two hundred thirteen".