Base | Representation |
---|---|
bin | 1010010011011010011… |
… | …11111001101000100101 |
3 | 1020211210021110200012001 |
4 | 11021231033321220211 |
5 | 21300013132444140 |
6 | 430345025325301 |
7 | 34401644034565 |
oct | 5115517715045 |
9 | 1224707420161 |
10 | 354020203045 |
11 | 1271591a2403 |
12 | 58740796831 |
13 | 274cb7449b2 |
14 | 131c5764da5 |
15 | 931ee69e9a |
hex | 526d3f9a25 |
354020203045 has 4 divisors (see below), whose sum is σ = 424824243660. Its totient is φ = 283216162432.
The previous prime is 354020203013. The next prime is 354020203051. The reversal of 354020203045 is 540302020453.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 540302020453 = 13 ⋅41561693881.
It can be written as a sum of positive squares in 2 ways, for example, as 257593806369 + 96426396676 = 507537^2 + 310526^2 .
It is a cyclic number.
It is not a de Polignac number, because 354020203045 - 25 = 354020203013 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 35402020300 + ... + 35402020309.
It is an arithmetic number, because the mean of its divisors is an integer number (106206060915).
Almost surely, 2354020203045 is an apocalyptic number.
It is an amenable number.
354020203045 is a deficient number, since it is larger than the sum of its proper divisors (70804040615).
354020203045 is an equidigital number, since it uses as much as digits as its factorization.
354020203045 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 70804040614.
The product of its (nonzero) digits is 14400, while the sum is 28.
Adding to 354020203045 its reverse (540302020453), we get a palindrome (894322223498).
The spelling of 354020203045 in words is "three hundred fifty-four billion, twenty million, two hundred three thousand, forty-five".
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